2022 NECO Chemistry Expo: Questions and Answers – Obj & Theory

Questions and Answers for NECO Chemistry 2022. In this post, I will provide you with free access to old Chemistry objectives and theory repeated problems. You’ll also learn how NECO Chemistry questions are constructed and how to respond to them.

SEE ALSO:

NECO CHEMISTRY PRACTICAL ANSWERS

NECO GCE Obj and Theory Questions and Answers

In Nigeria, the National Examinations Council (NECO) administers the Senior Secondary Certificate Examination and the General Certificate in Education in the months of June/July and December/January, respectively.

NECO Chemistry Essay Answers and Objectives 2022

On the day of the NECO Chemistry exam, the 2022 NECO Chemistry Answers will be uploaded here. For the answers, keep checking and reloading this page.

NECO 2022 Chemistry Answers are now being loaded…

NECO Chemistry OBJ Answers for Today…

Today’s Chemistry Essay Answers are as follows:

(1ai) (i)graphite (ii)diamond

(1aii) (i)carbon black (ii)animal charcoal

(1aiii) (i)An element’s attribute is a periodic function of its atomic number.
(ii)Elements are arranged in the periodic table in increasing atomic weight order.

1bii) Using: mole = no; number of atoms/constant avogadro’s 0.5=no; number of atoms/6.023*1023 no; number of atoms = 0.5*6.02*1023=3.012*1023atom

1ci) According to Faraday’s first law of electrolysis, the chemical deposition caused by current flow through an electrolyte is directly proportional to the amount of electricity (coulombs) carried through it.

2O2- + 9e —>2O2 no; of electron = 4 Q=20300C (1cii) 2O2- + 9e —>2O2
F=96500C; G.M.V =22.4dm3; G.M.V =22.4dm3; G.M.V =22.4d
Mole=Q/n,f
Mole=20300/4*96500
Mole=20300/386000
Mole=0.05mol
=vol/G.M.V 0.05=vol/22.4 vol=0.05*22.4 vol=1.12dm3 recall

(1di) Using H2SO4 H+ SO4-1 H+ OH- A+ 1di) Using H2SO4 H+ SO4-1 H+ OH- A+ 1di) Using H2SO4 H OH + e —-> anode OH -\s2OH+(aq)+2OH(aq)—->2H²O(s)+O²(aq)

(1dii)
-Electrolyte- (I)teraoxosulphate(iv)acid tabulate (II)
Ester

(III)phenol (non-electrolyte)

(1ei)\s(i)mercury

(1eii) (I)no; electron mass number in Y =16 (II)no; mass number in Y =16+18=34 (III)sulphur

(2ai) Basicity is the number of hydrogen ions that can be replaced in an acid (2aii)
(I) —> 3; (II) —> 1; (III) —> 2; (IV) —> 3; (V) —> 1; (IV) —> 2; (V

(2bi) (i)Concentration (ii)Temperature (iii)Pressure

(2bii) (i)Light (ii)Temperature (iii)Reactant Nature

(2ci) Compile a S/N table; (I) (II)

Methyl orange and phenolphthalein are indicators.

In acid, there are two colors: red and colorless.

At the end, the color is orange and it is colorless.

Yellow and pink for the foundation color.

Strong acid and weak base, weak acid and strong base, strong acid and strong base

(2cii)

1s2,2s2,2p3 (i)Nitrogen

Fluorine —> 1s2,2s2,2p5

Aluminium —> 1s1,2s2,2p6,3s2,3p1

(2di)

(I)Hydrogen gas escapes.

(II)The purple color fades and becomes colorless.

(III)It results in the formation of a black carbon residue.

(2dii)

(i)It can be used as a quick source of energy.

(ii)it is used in the confectionery industry.

(4ai) (I)Burning necessitates heating, whereas corrosion does not. (II)Boiling takes place at a specific temperature, whereas evaporation takes place at any temperature.

(4b)

A concentration solution is one that forms when a big amount of a chemical dissolves in a little amount of water.

(4bii)

(i)in the electrochemical series, the ion’s location

(ii)concentration ion ion ion ion ion ion

(iii) type of electrodes

(4ci)

(27*2)+(32*3)+(16*12) =54+96+192=342glmol Al2(SO4)3=(27*2)+(32*3)+(16*12) Al2(SO4)3=(27*2)+(32*3)+(16*12) Al2(SO

(4cii)

Teraoxosulphate of aluminum (iv)

(4ciii)

1,2,3,-triol (i)Propane

(ii)Salt of potassium

(4di)

Tabulate.

-Detergent from Staples-

(i) In hard water, it does not develop scum.

(ii) They are non-biodegradable.

-Soapy detergent – (i)firms scum in hard water (ii)is biodegradable

 

(4dii)

(i)RCOOH

(ii)ROH

 

(4diii)

V1=300cm³.

P1=760mmHg

P2=800mmHg,

V2=?

Using the formula V1*P1 =V2*P2

300*700=V2*300

V2=300*760/800

V2=228000/800

V2=285cm³

(4div)

It has a +3 change.

(4dv)

+Al3+ (Aluminum ion)

(5ai)

Coal and coke are two types of coal.

(5aii)

NO2 nitrogen (iv) oxide (I)acidic

NO nitrogen (ii) oxide (II)neutral

(5aiii)

H2SO4/H2O CO HCOOH (g)

 

22.4 dm3 CO = 46 g HCOOH

X = 600g of HCOOH

CO(s) is created in the amount of 600*22.4/46=2.92dm3.

(5bi) (i)To standardize an acid or basic solution

(ii)To calculate the purity and impurity of an acid in a base.

 

(5bii)

(I)density

(II)solubility

(5ci)

2NaCl2(aq) + Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe(OH)2 Fe (s)

Sodium chloride and iron (II) hydroxide are the primary products.

 

(5cii)

(I)FeCl²

Iron (II) chloride (II)

 

(5di)

(I)it has a somewhat higher density than air.

(II)it is water soluble to a degree.

 

(5dii)

Rust occurs as a result of the development of hydrated iron (iii) oxide when exposed to oxygen. In other words, when it rusts, it turns a reddish brown color.

[18.11.20 07:04] BMS
[From Horlajoy] A laky powder is generated with new qualities and a permanent transformation that is irreversible.

2Fe2O3 XH2O = Fe(s) + 3O3(g) + XH2O(s) (s)

 

(5diii)

35 g dry hydrogen mas

A compound’s dry hydrogen + oxygen vapour mass equals 440g.

The compound’s organic vapour mass is 440g-35g=405g.

Vapour V.D = mass of vapour/mass of H2 of equal volume

405/35 =11.51

11.6 V.D.

The vapour’s R.m.m =V.D *2

11.6*2=23.2

 

(6ai)

(I)Efflorescence

(II)Isotope

(III)Isomerism

 

(6aii)

Kipps’ device

 

(6aiii)

(i)Temperature

(ii)Enthalpy value change

 

(6bi) Polymerisation is the process of combining smaller nuclei to generate larger nuclei.

(6bii)

(i)Polymerization addition

(ii) Condensation Polymerization

 

(6biii)

=4.583r105 OH-

Since the [H+] [OH] = 10-14

[H^+] [4.583*10^-⁵]=10^-¹⁴

[H^+]=1*10^-¹⁴/4.583*10^-⁵

[H^+]=0.22*10^-⁹

[H^+]=2.2*10^-¹⁰moldm³

PH= – logH+ since

PH=-log10 2.2*10-10

PH=0.34+10

PH=10.34

 

(6ci)

—-> carbohydrate (I)

—-> R-OH and R-CHO (II)

 

(6cii)

(I)Composition of brass; copper and zinc

 

-brass uses- (i)it’s used to make hammers (ii) it’s employed in applications that require low corrosion resistance.

 

(II)composition of steel; iron and carbon

-Steel applications-

(i) It is used on roofs

(ii) it is used as an outside wall cladding

(6ciii)

(i)Fermentation

(ii)Ethene-based preparation

(6iv)

This is due to the fact that there are just a few molecules that can receive protons.

SEE ALSO: NECO TIMETABLE

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The following NECO Chemistry questions are examples of what you might expect on the NECO exam in 2022.

1. It is known how much energy is needed for effective collisions between responding particles.
A) Activation energy

B) Bond energy

(C) kinetic energy

D) Energy potential

2. The hydroxonium H3O+H3O+ is generated when H2OH2O and H+H+ form a link.

A) Nominative

Covalent (B)

(C) Electrovalent

(D) Ionic

 

3. The oxides X2O,XOX2O,XO,XO, and XO2.XO2 are formed by an element XX. This occurrence exemplifies the law of

A) Mass conservation

B) Proportions that are fixed

C) Massive mobilization

D) Proportions in multiples

 

4. What is the number of moles of oxygen in 1.20410241.2041024 molecules?

NB: Avogadro’s constant (NA) =6.021023=6.021023=6.021023=6.021023=6.021023=6.021023=6.021023=6.021023=6.021023=

A. 1

B. 2

C. 3

D. 4

5. Which of the following solids assertions is true?

A) Solid particles are less ordered than liquid particles.

B) Solids have a lower density than liquids.

C) The kinetic energy of solid particles are higher than those of liquids.

D) Solid particles are difficult to crush.

 

6. Which of the following apparatuses can be used to correctly measure the volume of a liquid?

(A) Beaker

B) Flask with a conical shape

C) Cyclinder measurement

(D) Pipette

 

7. PVT=KPVT=K is a combination of the general gas equations PVT=KPVT=K and PVT=KPVT=K.

A) The rules of Boyle and Charles

B) The laws of Boyle and Graham

C) The laws of Charles and Graham

D) The laws of Dalton and Graham

8. What is an example of the spread of a flower’s smell in a garden?

(A) Brownian motion

(B) Diffusion

(C) Osmosis is a type of osmosis that occurs when water is

(D) Tynadal impact

9. Because [H = 1.00, C = 12.0, O = 16], propane and carbon (IV) oxide diffuse at the same rate .0]

Options

They’re both gases, for starters.

B) They have carbon in their molecules.

C) Their respective molecular masses are the same.

D) They’re both denser than air.

 

1O. The energy released when an electron is added to an isolated gaseous atom is

(A) Atomization

(B) Electronegativity

C) Affinity for electrons

(D) Ionization

11. Calcium sulphate and calcium hydrogen carbonate are found in a sample of hard water. As a result, total hardness can be reduced by

A. boiling the water

B. adding excess calcium hydroxide.

C. adding calcium hydroxide in a determined amount

D. sprinkling with sodium carbonate

E. incorporating magnesium hydroxide into the mix 12. If litmus solution is supplied to the anode compartment during the electrolysis of copper II sulphate between platinum electrodes,

A. the litmus changes color to blue, but no gas is produced.

B. the litmus turns blue, indicating the release of oxygen

C. the litmus becomes blue, releasing hydrogen

D. the litmus turns red, releasing oxygen

E. the litmus changes color from red to colorless.

13. Saponification is the reaction of an organic acid and an alcohol in the presence of an acid catalyst.

A. Dehydration

B. Esterification

C. Hydrolysis

D. hydration

 

14. CH3COOH and CH2=CH2 are the IUPAC designations for the compounds, respectively.

A. acetic acid and ethane

B. ethanoic acid and ethene

C. methanoic acid and ethylene

D. ethanol and ethene

E. acetic acid and ethylene

15. Given that 30cm3 of oxygen diffuses through a porous pot in 7 seconds, how long will 60cm3 of chlorine take to diffuse through the same pot, assuming that the vapour densities of oxygen and chlorine are 16 and 36, respectively?

A. 9.3 sec

B. 14 sec

C. 21 sec

D. 28 sec

E. 30.3 sec

16. A chemical reaction is considered to be “heated” when heat is absorbed during it.

A thermodynamic equation

B. exothermic

C. isothermal

D. endothermic

E. thermostatic

17. The process of converting large hydrocarbon molecules into smaller molecules by heating them at a high temperature in the presence of a catalyst is known as

A. decomposition

B. Polymerization

C. Cracking

D. decomposition

E. distillation

The pH of four solutions W, X, Y, Z are 4, 6, 8, 10 respectively, therefore

A. none of these solutions is acidic

B. the pH of Y is made more acidic by addition of distilled water

C. Z is the most acidic solution

D. W is the most acidic solution

E. X is neutral

19. When each of the potassium, magnesium, and iron nitrates is heated,

A. All nitrates break down into their oxides.

B. Magnesium nitrate produces nitrite and oxygen.

C. the oxides are formed by the nitrates of iron, magnesium, and iron.

D. Iron nitrate produces nitrite and oxygen.

E. the magnesium nitrate is not decomposed

 

2O. Which of the metals listed below cannot be used to replace hydrogen in water or steam?

A. Sodium

B. Magnesium

C. Iron

D. Calcium

E. Copper

 

21. In a test tube, a small amount of solid ammonium chloride (NH4Cl) was gently heated, the solid gradually disappearing to form two gases. On the colder part of the test tube, a white hazy deposit was later discovered. The ammonium chloride is considered to have gone through a transformation.

A. distillation

B. Sublimation

C. Precipitation

D. Evaporation

E. Decomposition

22. Because the elements P, Q, R, and S each contain 6, 11, 15, and 17 electrons,

A. P will form an electrovalent connection with R.

B. Q and S will create a covalent connection.

C. With S, R will form an electrovalent connection.

D. Q and S will form an electrovalent bond.

E. Q and R will create a covalent bond.

 

23. With chlorine, an element X generates the following compounds: XCl4, XCl3, and XCl2. This is an example of the

A. multiple proportions law

B. chemical proportions law

The law of simple proportions (Law of Simple Proportions)

D. the law of mass conservation

E. the law of fixed proportions

 

24. In potassium chlorate, the oxidation state of chlorine is

A. +1

B. +2

C. +3

D. +5

E. +7

When air including the gases oxygen, nitrogen, carbon dioxide, water vapour, and rare gases is passed through alkaline pyrogallol and subsequently over quicklime, only two gases remain:

A. nitrogen and carbon dioxide.

B. The rare gases

C. nitrogen and oxygen (C)

D. Nitrogen and rare gases

E. Nitrogen, carbon dioxide, and the rare gas argon

26. Which of the following statements is incorrect?

A. A gas’s kinetic energy is related to its temperature on average.

B. The volume of a gas grows as the pressure increases at constant temperature.

C. The volume and pressure of a gas are inversely proportional.

D. The volume of a gas is proportional to its temperature.

E. Molecules collide with each other in an inelastic manner.

28. When sodium chloride and metallic sodium are each dissolved in water

A. both processes are exothermic

B. both processes are endothermic

C. the dissolution of metallic sodium is endothermic

D. the dissolution of metallic sodium is exothermic

E. the dissolution of sodium chloride is explosive

 

The periodic categorization of elements is an orderly organization of the elements in terms of their properties.

A. Atomic Weights

B. Isotopic Weights

C. Molecular Weights

D. Atomic Numbers

E. Atomic Masses

3O. In the reaction between sodium hydroxide and sulphuric acid solutions, what volume of 0.5 molar sodium hydroxide would exactly neutralise 10cm3 of 1.25 molar sulphuric acid?
A. 5cm3
B. 10cm3
C. 20cm3
D. 25cm3
E. 50cm3

SEE ALSO:

NECO Physics Questions and Answers Expo

NECO Mathematics Questions and Answers theory / Objective

NECO English Language: Theory/Essay Questions and Answers is Out

NECO Chemistry Questions And Answers 2022 (Paper 2)

Don’t be concerned about the 2022 NECO Chemistry Questions And Answers. All you have to do now is keep refreshing this page for this year’s NECO Chemistry Questions And Answers. In a few minutes, it will be put here.

How to Pass 2022 NECO Chemistry Examination

The tips below will ensure that you pass the NECO Chemistry exam in 2022 with flying colors.

1. Make a goal for yourself and work toward achieving it.

I am confident that you have opted to pass NECO Chemistry 2022. The next step is to define goals for yourself.

You’ve promised yourself, “I’ll get an A in Neco Chemistry 2022,” but that’s not all. You must devise a strategy for achieving your goal. Make a schedule and a master strategy to reach your objectives.

2. Get the Recommended Textbook

In most cases, Neco recommends literature for the exam. However, you are allowed to utilize any decent Chemistry textbook to prepare for the NECO 2022 exam, with the exception of NECO Literature in English, where specified novels are required.

Some textbooks are more challenging to comprehend than others. If you’re having trouble understanding a topic, invest in a textbook that will help you learn the material and make your life easier.

In most circumstances, Neco suggests reading material for the exam. With the exception of NECO Literature in English, where specific novels are required, you are free to use any excellent Chemistry textbook to prepare for the NECO 2022 exam.

Some textbooks are more difficult to grasp than others. Invest in a textbook if you’re having problems grasping a topic. It will help you learn the material and make your life easier.

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