# NECO Physics Practical Questions and Answers 2022/2023 Examination

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## Today’s NECO Practical Physics Answers

No (1)

Tabulate.
S/N; 1|2|3|4|5|

M|g; 40.0|35.00|30.00|25.00|20.00|

θ°; 41.80|35.70|30.00|24.60|19.47|

ϕ=(90-θ°); 48.20|54.30|60.00|65.40|70.53|

Cosϕ; 0.6665|0.5835|0.5000|0.4163|0.3333|

(1axi)
Slope , S=Δm|g/ΔCosϕ
=(40-20)g/0.6665-0.3333
S= 20g/0.3332=60.024g

(1axii)
K=s/2 =60.024g/g= 30.012g

(1axiii)
-Precautions-
(i) I avoided error due to parallax when reading from the protector
(ii) I ensured that the force board is firmly and correctly clamped to the retort stand

(1)
Graph

1bi)
(i)The have the same magnitude/size
(ii)They can be obtained/calculated by the same means

(1bii)

(1bii)
T²= 9²+12²
T= √81+144
T= √225
T= 15N

No (3)
Tabulate
S/N; 1|2|3|4|5|

R/Ω; 2.00|4.00|6.00|8.00|10.00|

L/cm; 50.00|66.70|75.00|80.00|83.30|

B/Ω^-¹; 0.500|0.250|0.167|0.125|0.100|

Δ/cm; 1.000|0.499|0.333|0.250|0.200|

(3xiii)
Slope ,S=ΔB/Ω^-¹/ΔΔ/cm =0.5-0.1/1.0-0.2=0.4/0.8=0.5
Slope =0.5Ω^-¹/cm

(3xiv)
K=S^-¹= 1/5=1/0.5Ω^-¹/cm =2Ωcm

(3xv)
-precautions-
(i) I avoided error due to parallax when reading from the potentiometer
(ii) I ensured that the wire are tightly connected.

(3)
Graph

(3bi)
(i) potentiometer give exact value of potential difference while voltmeter draws apart of the current
(ii) potentiometer can be used for measuring the internal resistance of a cell which cannot be done with voltmeter

(3bii)
x/R= c/100-c
x/R= 20-0/100-20
x/20= 20/80
x= 20*20/80
x= 400/80
x= 5Ω

The questions below are for practice not the 2022 Physics Practical questions.

1(a)

You are provided with two retort stands, two metre rules, pieces of thread and other necessary apparatus. (i) Set up the apparatus as illustrated above ensuring that the strings are permanently 10cm from either end of the rule.

(ii) Measure and record the length L = 80cm of the two strings.

(iii) Hold ends of the rule and displaces the rule slightly, then release so that it oscillates about a vertical axis through its centre.

(iv) Determine and record the time t for 10 complete oscillations. (v) Determine the period T of oscillations.

(vi) Evaluate log T and log L. (vii) Repeat the procedure for four other values of L = 70cm, 60cm, 50cm, and 40cm.

(ix) Plot a graph with log T on the vertical axis and log L on the horizontal axis.

(x) Determine the slope, s and the intercept, e on the vertical axis, of the graph.

(xi) State two precautions taken to ensure accurate results.

(b)(i) Define simple harmonic motion

(ii) Determine the value of L corresponding to t = 12s from the graph in 1 (a).

2(a) You are provided with a beaker, a thermometer, a stirrer, stop watch/clock, measuring cylinder, table salt, water and other necessary materials.

(i). Measure 200cm3 of water into the beaker.

(ii). Heat the water until it boils steadily for about 2 minutes

(iii). Read and record the boiling point bo.

(iv). Add table salt of mass M = 10.0g to the boiling water and stir continuously until another boiling point bi is attained.

(v). Read and Record bi.

(vi). Evaluate θi = (bi – bo )

(vii) Using the same mixture, repeat the procedure four more times by adding 10.0g of salt each times to give the cumulative mass Mi of salt as 20g. 30g. 40g. and 50g.

(viii) in each case, allow the mixture to boil steadily for at least 2 minutes then read and record the boiling point bi.

(x). Plot a graph with Mion the vertical axis and θi on the horizontal axis.

(xi). Determine the slope, s, of the graph.

(xii). State two precautions taken to ensure accurate results.

(xiii). Define the boiling points of a liquid

(xiv). What effect do impurities have on the boiling point of a liquid?

3(a) You are provided with cells, a potentionmeter, an ammeter, a voltmeter, a bulb, a key, a jockey and other necessary materials.

(i) Measure and record the e.m.f. of the battery

(ii) Set up a circuit as shown in the diagram above.

(iii) Close the key K and use the jockey to make a firm contact at J on the potentiometer wire such that PJ = x = 10cm.

(iv) Take and record the voltmeter reading V and the corresponding ammeter reading I.

(v) Evaluate the log V and log I.

(vi) Repeat the procedure for five values of x = 20cm, 30cm, 40cm, 50cm, and 60cm,

(viii) Plot a graph with log I on the vertical axis, and log  V on the horizontal axis.

(ix) Determine the slope s, of the graph.

(x) Determine the intercept c, on the vertical axis.

(xi) State two precautions taken to ensure accurate results.

(b)(i) How is the brightness of the bulb affected as x increases? Give a reason for your answer.

(ii) List two electrical devices whose actions do not obey Ohm’s law.

### PHYSICS PRACTICAL ANSWERS 2022

1(a)(iii) Table of reading

(x)

Slope = ΔlogT/ΔlogL = LogT2 – LogT1/LogL2 – LogL1 = 0.098-(0.10)/0.00 – (-0.38)

= 0.098 + 0.10/0.00 + 0.38 = 0.198/0.38 = 0.52

The intercept, C on the vertical axis = 0.99

(I) I ensured strings were tight

(II) I avoided parallax error on metre rule

(III) I ensured smooth and regular oscillation in a horizontal plane.

(b)(i) Simple harmonic motion is the motion of a body whose acceleration is always directed towards, a fixed point and is directly proportional to the displacement from the fixed point.

(ii) T = t/n = 12/10 = 1.2s

;log 1.2 = 0.079

The value of LogL = 0.035 = 0.04

L = 1.1

GRAPH

bo = 98oC

S/Nm(g)bi(oC)θi = (bi-bo)1101002.02201024.03301046.04401068.055010810.0

(xi) Slope = Δmi/Δθi = mi2 – mi1/θ2 – θ1 = 50-5/10-1.0 =  45/9 = 5

(I) I ensured that the water was stirred gently

(II) I avoided parallax error on the thermometer and stopwatch; (III) I avoided zero error on stop watch.

(b) (i) This is the temperature of a liquid at which is saturated vapour pressure equals the external atmospheric pressure.

(ii) impurities raise the boiling point of a liquid.

GRAPH

 S/N I(cm) I(A) V(v) Log1 LogV 1 10.0 0.06 0.20 -1.22 -0.70 2 20.0 0.12 0.35 -0.92 -0.50 3 30.0 0.15 0.45 -0.82 -0.35 4 40.0 0.18 0.50 -0.75 -0.30 5 50.0 0.24 0.65 -0.62 -0.19 6 60.0 0.27 0.80 -0.57 -0.09

(ix)

Slope = ΔlogI/ΔlogV = logI2 – logI1/logV2 – logV1 = -0.28 – (-1.22)/0.1 – (-0.7)

= -0.28 + 1.22/0.1 + 0.7 = 0.94/0.8 = 1.175

(x) the intercept on the vertical axis = -04

(xi) (I) I opened tight terminals;

(II) I opened key when reading was not taken

(b)(i) Brightness of the bulb increases

Reason: Voltage across and current through the bulb increases

(ii) (a) Diode; (b) Transistor; (c) Filament bulb (d) Capacitor

GRAPH

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